5x^2-380x+80=0

Solution for 5x^2-380x+80=0 equation:

5x^2-380x+80=0

a = 5; b = -380; c = +80;
Δ = b2-4ac
Δ = -3802-4·5·80
Δ = 142800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{142800}=\sqrt{400*357}=\sqrt{400}*\sqrt{357}=20\sqrt{357}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-380)-20\sqrt{357}}{2*5}=\frac{380-20\sqrt{357}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-380)+20\sqrt{357}}{2*5}=\frac{380+20\sqrt{357}}{10}
$